3x^2=261

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Solution for 3x^2=261 equation:



3x^2=261
We move all terms to the left:
3x^2-(261)=0
a = 3; b = 0; c = -261;
Δ = b2-4ac
Δ = 02-4·3·(-261)
Δ = 3132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3132}=\sqrt{36*87}=\sqrt{36}*\sqrt{87}=6\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{87}}{2*3}=\frac{0-6\sqrt{87}}{6} =-\frac{6\sqrt{87}}{6} =-\sqrt{87} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{87}}{2*3}=\frac{0+6\sqrt{87}}{6} =\frac{6\sqrt{87}}{6} =\sqrt{87} $

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